(x^2+3)/(x-1)=-2

Solution for (x^2+3)/(x-1)=-2 equation:

(x^2+3)/(x-1)=-2

We move all terms to the left:

(x^2+3)/(x-1)-(-2)=0


Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R


We add all the numbers together, and all the variables

(x^2+3)/(x-1)+2=0

We multiply all the terms by the denominator


(x^2+3)+2*(x-1)=0

We multiply parentheses

(x^2+3)+2x-2=0

We get rid of parentheses

x^2+2x+3-2=0

We add all the numbers together, and all the variables

x^2+2x+1=0

a = 1; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{2}=-1$